This is my updated code, it still doesn't work. It returns day for all cases of Feb. 29th, when it should only return day if it is a leap year, if it is not a leap year 1 should be returned. publi The year (in either 2 or 4 digits) The month (in either 2 digits, First 3 letters of the month or the entire word of the month). The date (it will be the actual date of the month). The day (the day at the given date – like Sun, Mon, Tue, etc.) Concerning computer systems, there are quite a lot of parameters that can be used to associate with
get a new Date instance representing tomorrow that has no time component to it (only year, month & day). You are using a date-with-time-of-day class to represent a date-only value. Square peg, round hole. Instead, use the date-only class: LocalDate. Avoid legacy classes
Date(year, month, day) is deprecated since JDK version 1.1 ! See the GregorianCalendar JavaDoc: Constructs a GregorianCalendar with the given date set in the default time zone with the default locale.
In this I get leap & ordinary year and month, but I don't know how to get day of the given date month year. And also having one question: 1800 and 1900 are ordinary year but I get these years are leap year.

In this short tutorial, we'll look at how to extract the year, month and day from a given Date in Java. We'll be looking at how to extract these values using the legacy java.util.Date class and also by using the new date-time library of Java 8. In Java 8, a whole new date and time library was introduced for a number of good reasons.

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java date year month day